Text tool

Milk Fat Standardisation Calculator

Solve a two-stream milk-fat mass balance for a chosen total blend mass and target fat mass fraction.

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mA = total mass × (target fraction − fraction B) / (fraction A − fraction B). mB = total mass − mA. Fat mass = mA × fraction A + mB × fraction B. Fractions are kg fat/kg stream, from 0 to 1, not percentages or volume fractions.

Two-stream mass conservation only, with no losses or reactions. Streams must have distinct fat mass fractions; the target must lie between them, including the endpoints. No volume/density conversion, product specification, processing, nutrition or safety judgment is supplied.

FAO dairy processing reference: standardisation and material balance. The calculator solves mass and fat conservation algebraically.

A QUICK WALKTHROUGH

How to use this tool

  1. Enter a positive total blend mass in kilograms.
  2. Enter distinct stream fat mass fractions and a target between them, as kg fat per kg stream.
  3. Calculate, then copy or download the report.

Formula and units

mA = total mass × (target fraction − fraction B) / (fraction A − fraction B). mB = total mass − mA. Fat mass = mA × fraction A + mB × fraction B. Fractions are kg fat/kg stream, from 0 to 1, not percentages or volume fractions.

Scope

Two-stream mass conservation only, with no losses or reactions. Streams must have distinct fat mass fractions; the target must lie between them, including the endpoints. No volume/density conversion, product specification, processing, nutrition or safety judgment is supplied.

Local processing

Inputs stay in your browser. Copy and TXT export include the inputs, calculation, formula and scope.

Reference

FAO dairy processing reference: standardisation and material balance. The calculator solves mass and fat conservation algebraically. https://www.fao.org/4/t1265e/t1265e.pdf

GOOD TO KNOW

Common questions

Can I enter fat percentage?

Convert percent to a mass fraction first: 4% by mass is 0.04 kg/kg. Volume fractions are not supported.

What if both streams have equal fat fractions?

The split is not uniquely determined by fat conservation, so equal fractions are rejected.